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Quadratic equations are a fundamental part of algebra and often arise in various math problems. In this article, we will explore how to solve the quadratic equation x² – 11x + 28 = 0 – 11x + 28 = 0x2−11x+28=0 through factorization. We will also provide a step-by-step guide and explanation, including a video link for additional clarity.

Now that we understand the form of the equation, let’s move on to solving it by factorization. Factorization involves breaking down the equation into two simpler binomials that, when multiplied, give the original quadratic equation.

- The numbers −7-7−7 and −4-4−4 satisfy these conditions because: −7×−4=28and−7+(−4)=−11-7 \times -4 = 28 \quad \text{and} \quad -7 + (-4) = -11−7×−4=28and−7+(−4)=−11
- - We can now rewrite the equation by splitting the middle term (-11x): x2−7x−4x+28=0x^2 – 7x – 4x + 28 = 0x2−7x−4x+28=0
  - In conclusion, the quadratic equation x2−11x+28=0x^2 – 11x + 28 = 0x2−11x+28=0 can be easily solved using factorization. By identifying two numbers that multiply to the constant term and add up to the coefficient of the middle term, we can break down the equation into two binomials. In this case, the solutions are x=7x = 7x=7 and x=4x = 4x=4.